Transmission And Substation Foundations - Technical Design Manual (TD06088E)

= 4 √ (30 x 10 6 x 0.396) / (15 x 1.5) = 26.96

Equation 7-21

R

I max

= (15 x 12) / 26.96 = 6.7

= (2 x 30 x 106 x 0.396) / 26.96 2 = 32.69 kips

P cr

CHANCE® HELICAL TYPE SS150 SQUARE SHAFT FOUNDATIONS PHYSICAL PROPERTIES, TABLE 7-1 MODULUS of ELASTICITY (E p ) MOMENT of INERTIA (I p )

SHAFT DIAMETER (D)

30 x 10 6 psi

0.396 in 4

1.5 in

DESIGN EXAMPLES

Foundation Details Figure 7-36

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